with an approximate solution for RL > 0 Ω:
EAS=
2IL·R· LL·(Vbb
+
|VOUT(CL)|)·
ln
(1+
IL·RL
|VOUT(CL)|
)
BTS 410 F2
Maximum allowable load inductance for
a single switch off
L = f (IL ); Tj,start = 150°C,TC = 150°C const.,
Vbb = 12 V, RL = 0 Ω
L [mH]
10000
Typ. transient thermal impedance chip case
ZthJC = f(tp, D), D=tp/T
ZthJC [K/W]
10
1
1000
D=
0.5
0.1
0.2
0.1
0.05
0.02
0.01
0
0.01
1E-5 1E-4 1E-3 1E-2 1E-1 1E0 1E1
100
1.5 1.75 2 2.25 2.5 2.75 3
IL [A]
tp [s]
Semiconductor Group
8