LTC6990
APPLICATIONS INFORMATION
Step 2: Calculate KVCO and f(0V)
Next, calculate the intermediate values KVCO and f(0V) using
Equations (3b) and (3c).
K VCO
=
100kHz − 10kHz
4V − 1V
=
30kHz/V
f(0V) = 100kHz + 30kHz/V • 1V = 130kHz
Step 3: Calculate and Select RVCO
The next step is to use Equation (3d) to calculate the cor-
rect value for RVCO.
RVCO
=
8
1MHz • 50k
• 1V • 30kHz/V
=
208.333k
Select RVCO = 210k.
Step 4: Calculate and Select RSET
The final step is to calculate the correct value for RSET
using Equation (3e).
RSET
=
8
•
1MHz • 50k
(130kHz − 1V • 30kHz/V)
=
62.5k
Select RSET = 61.9k
In this design example, with its wide 10:1 frequency
range, the potential output frequency error due to VSET
error alone ranges from less than ±1% when VCTRL is at
its minimum up to ±36% when VCTRL is at its maximum.
This error must be accounted for in the system design.
Depending on the application’s requirements, the non-
inverting VCO circuit in Figure 13 may be preferred for
this wide of a frequency variation as its maximum inac-
curacy due to VSET error is only ±9% and can be reduced
to only ±3% with a small change to the voltage tuning
range specification.
Reducing VSET Error Effects in VCO Applications
Figure 13 shows a VCO that reduces the effect of ΔVSET
by adding an op-amp to make VCTRL dependent on VSET.
This circuit also has a positive transfer function (the out-
put frequency increases as VIN increases). Furthermore,
for positive VIN voltages, this circuit places the greatest
absolute frequency error at the highest output frequency.
Compared to the simple VCO circuit of Figure 11, the
absolute frequency error is unchanged. However, with
the maximum absolute frequency error (in Hertz) now
occurring at the highest output frequency, the relative
frequency error (in percent) is greatly improved.
0.4V TO 4V
VIN
R3
100k
3V
10kHz TO 100kHz
fOUT
OE
OUT
LTC6990
3V
3V
1/2
LTC6078
VSET
RVCO
VCTRL 75k
R4
30.1k
C4
33pF
GND
V+
SET
DIV
6990 F13
C1
0.1µF
R1
1M
DIVCODE = 3
(NDIV = 8, Hi-Z = 0)
R2
280k
RSET
249k
fOUT
=
1MHz
•
50kΩ
•
RVCO
NDIV • RVCO RSET
+
VIN
VSET
−
1
•
R4
R3
IF R4 = RVCO , THE EQUATION REDUCES TO:
R3 RSET
fOUT
=
1MHz • 50kΩ •
NDIV • RSET
VIN
VSET
= VIN • 25kHz/V
Figure 13. VCO with Reduced ∆VSET Sensitivity
6990fc
18
For more information www.linear.com/LTC6990